:分式-小专题
小专题(十四) 分式的运算
题组1 分式的混合运算
1.计算:
(1)a+1(a)+a2-1(a-1);
(2)x2-1(2x)÷x+1(x);
(3)(x-2(x)-x+2(x))÷x-2(4x);
(4)(巴中中考)a+1(2a)-a2-1(2a-4)÷a2-2a+1(a-2);
(5)(1+x-1(2))÷x2-2x+1(x+1);
(6)(南充中考)(a+2-a-2(5))·3-a(2a-4);
(7)x-1(2-x)÷(x+1-x-1(3));
(8)(2-x(1)+1)÷x2-4(x-3)·x2+4x+4(x).
题组2 分式的化简求值
2.先化简,再求值:(x-1(1)-x+1(1))·(x-1),其中x=2.
3.(湘潭中考)先化简,再求值:(x-1(6)+x2-1(4))÷x-1(3x+2),其中x=2.
4.(资阳中考)先化简,再求值:(a+a+2(1))÷(a-2+a+2(3)),其中,a满足a-2=0.
5.(乐山中考)化简并求值:(x-y(1)+x+y(1))÷x2-y2(2x-y),其中x、y满足|x-2|+(2x-y-3)2=0.
6.(泰州中考)先化简,再求值:(1-x+2(3))÷x2+2x(x-1)-x+1(x),其中x满足x2-x-1=0.
7.(南昌中考)先化简,再求值
题组1 分式的混合运算
1.计算:
(1)a+1(a)+a2-1(a-1);
(2)x2-1(2x)÷x+1(x);
(3)(x-2(x)-x+2(x))÷x-2(4x);
(4)(巴中中考)a+1(2a)-a2-1(2a-4)÷a2-2a+1(a-2);
(5)(1+x-1(2))÷x2-2x+1(x+1);
(6)(南充中考)(a+2-a-2(5))·3-a(2a-4);
(7)x-1(2-x)÷(x+1-x-1(3));
(8)(2-x(1)+1)÷x2-4(x-3)·x2+4x+4(x).
题组2 分式的化简求值
2.先化简,再求值:(x-1(1)-x+1(1))·(x-1),其中x=2.
3.(湘潭中考)先化简,再求值:(x-1(6)+x2-1(4))÷x-1(3x+2),其中x=2.
4.(资阳中考)先化简,再求值:(a+a+2(1))÷(a-2+a+2(3)),其中,a满足a-2=0.
5.(乐山中考)化简并求值:(x-y(1)+x+y(1))÷x2-y2(2x-y),其中x、y满足|x-2|+(2x-y-3)2=0.
6.(泰州中考)先化简,再求值:(1-x+2(3))÷x2+2x(x-1)-x+1(x),其中x满足x2-x-1=0.
7.(南昌中考)先化简,再求值
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